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Communication Systems - Engineering

Q1:

Bandwidth for practical PCM system is (where n is no. of channels, N length of PCM codes)

A 2n N fm Hz

B 4n fm Hz

C 2n fm

D (N + 1)fm

ANS:A - 2n N fm Hz

BWpcm(min) = Nnfm Hz.
BWpcm(max) = 2Nnfm Hz.