Consider a sampled signal y(t) = 5 x 10-6 x(t) where x(t) = 10 cos (8p x 103)t and ts = 100 μ sec. when y(t) is passed through an ideal low-pass filter with a cut off frequency of 5 kHz, the output of the filter is-A-5 x 10 6 cos (8p x 103)tB-5 x 10 5 cos (8p x 103)tC-5 x 10 1 cos(8p x 103)tD-10 cos(8p x 103)t-B-5 x 10 5 cos (8p x 103)t

Question

APTITUDE CRACK · Accepted Answer

B 5 x 10 5 cos (8p x 103)t Y(t) = 5 * 10^ 6x(t), Here x(t) = 10cos(8p*10^3)t, = 5 * 10^ 6 * 10cos(8p * 10^3)t, = 5*10^ 5 cos(8p*10^3)t.

Communication Systems - Engineering

Consider a sampled signal y(t) = 5 x 10^-6 x(t) where x(t) = 10 cos (8p x 10³)t and t_s = 100 μ sec. when y(t) is passed through an ideal low-pass filter with a cut off frequency of 5 kHz, the output of the filter is

For help Students Orientation
Mcqs Questions

Quick Links

Newsletter

Communication Systems - Engineering

Consider a sampled signal y(t) = 5 x 10-6 x(t) where x(t) = 10 cos (8p x 103)t and ts = 100 μ sec. when y(t) is passed through an ideal low-pass filter with a cut off frequency of 5 kHz, the output of the filter is

Solution

For help Students Orientation Mcqs Questions

Consider a sampled signal y(t) = 5 x 10^-6 x(t) where x(t) = 10 cos (8p x 10³)t and t_s = 100 μ sec. when y(t) is passed through an ideal low-pass filter with a cut off frequency of 5 kHz, the output of the filter is

For help Students Orientation
Mcqs Questions