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Memory and Storage

Q1:

For the given circuit, which of the following is correct?

A The number 5 is being written to the memory at address location 203.

B The chip has not been enabled, since the EN terminal is 0; therefore, nothing will be written to the chip and the output is tri-stated.

C Decimal 10 is being written into memory location 211.

D The read/write line is LOW; therefore, decimal 5 is being stored at memory location 211.

ANS:C - Decimal 10 is being written into memory location 211.

As the CS is active low when 0 is given as input it is activated, for read and write the input is 0.

So as write is active low it is activated and the data given is 1010(b) = 10(d) and is written onto memory as 1101001(b) = 211(d).



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