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Boolean Algebra and Logic Simplification

Q1: For the SOP expression , how many 1s are in the truth table's output column?

A 1

B 2

C 3

D 5

ANS:C - 3

ABC' = 110.
A'BC = 011.
AB'C = 101.

Normally,
The three input truth table is,
A B C Y
0 0 0 0
0 0 1 1
0 1 0 1
0 1 1 1------>A'BC
1 0 0 1
1 0 1 1 ------>AB'C
1 1 0 1------->ABC'
1 1 1 1

Based on the expression, we consider the marked ones.
So, the answer is 3. Means 3 1's will come.



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