Digital Arithmetic Operations and Circuits

Q1: How many BCD adders would be required to add the numbers 97310 + 3910?

A 3

B 4

C 5

D 6

ANS:A - 3

Firstly write BCD code for 973
i.e 1001 0111 0011

BCD code for 39
i.e 0011 1001

Add both binary no's. i.e 1001 1010 1100
> than 9. so add 6 BCD code
Now result 1010 0001 0010
Again > 9. add 6
00001 0000 0001 0010 is finally our result,
Thus 3 times BCD adder used.



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