Shift Registers

Q1: If an 8-bit ring counter has an initial state 10111110, what is the state after the fourth clock pulse?

A 00000000

B 11110000

C 00010111

D 11101011

ANS:A - 11101011

1. For the 1st clk pulse, it would be, 01011111
2. For the 2nd clk pulse, it would be, 10101111
3. For the 3rd clk pulse, it would be, 11010111
4. For the 4rth clk pulse, it would be, 11101011

So answer is 11101011.



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