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Communication Systems

Q1: If in a broadcasting studio, a 1000 kHz carrier is modulated by an audio signal of frequency range 100-5000 kHz, the width of channel is __________ kHz.

A 5

B 4.9

C 995

D 10

ANS:D - 10

i) Width of sideband = 5000 -100.
= 4900 Hz.

ii) - Max. frequency of USB = 1000 + 5 = 1005 kHz.
- Min. frequency of USB = 1000 + 0.1 = 1000.1 kHz.

iii) - Max. frequency of LSb = 1000 - 0.1= 999.9 kHz.
- Min. frequency of LSB = 1000 - 5 = 995 kHz.

iv) Width of channel = 1005 - 995 = 10 kHz.



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