Combinational Logic Analysis

Implementing the expression with NOR logic, we get:

A (A)

B (B)

C (C)

D (D)

ANS:A - (A)

According to De-Morgan's Theorem.
(A'.B')' = (A+B).
So, ((A'.B') + (C+D+E))' ==> (A+B) + (C+D+E)'.

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