Shift Registers

Q1: In a 4-bit Johnson counter sequence there are a total of how many states, or bit patterns?

A 2

B 1

C 4

D 8

ANS:D - 8

In Johnson counter, the number of states =2 * (number of flip flops).

4 flip flops for 4-bits number.

Numbers of states = 2 * 4 = 8.

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