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Probability

Q1: In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

A
1
3

B
3
4

C
7
19

D
8
21

E
9
21

ANS:A -

1
3

Total number of balls = (8 + 7 + 6) = 21.

Let E = event that the ball drawn is neither red nor green
= event that the ball drawn is blue.
n(E) = 7.
P(E) = n(E) = 7 = 1 .
n(S) 21 3



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