Q1:

In a repetitive-pulse RC integrator circuit, what would the steady-state voltage equal at the end of the fifth pulse? Assume a V_in of 20 V.

ANS:B - 14.62 V

First pulse => During the first pulse, the capacitor charges. The output voltage reaches,
12.64 V (63.2% of 20 V).

Between first and second pulses => The capacitor discharges and the voltage decreases to 36.8% of the voltage at the beginning of this interval: 0.368 (12. 64 V) = 4.65 V.
Second pulse => (20 - 4.65) V = 15.35 V.

Between second and third pulse = > 0.368 (15.35) = 5.64 V.
Third pulse => (20 - 5.64) v = 14.36 V.

Between third and fourth pulse => 0.368 * (14.36) = 5.28 V.
Fourth pulse => (20 - 5.28) V = 14.72 V.

Between fourth and fifth pulse => 0.368 (14.72) = 5.41 V.
Fifth pulse => (20 - 5.41) V = 14.59 V.

=> 14.6 V approx.