Digital Arithmetic Operations and Circuits - Technical MCQs

Q1:

Solve this BCD problem: 0100 + 0110 =

A 00010000BCD

B 00010111BCD

C 00001011BCD

D 00010011BCD

ANS:A - 00010000BCD

0100+0110=1010 in BCD addition (greater than 9 add 0110)
1010+0110=0001 0000