The BCD addition of 910 and 710 will give initial code groups of 1001 + 0111. Addition of these groups generates a carry to the next higher position. The correct solution to this problem would be to:-A-ignore the lowest order code group because 0000 is a valid code group and prefix the carry with three zerosB-add 0110 to both code groups to validate the carry from the lowest order code groupC-disregard the carry and add 0110 to the lowest order code groupD-add 0110 to the lowest order code group because a carry was generated and then prefix the carry with three zeros-D-add 0110 to the lowest order code group because a carry was generated and then prefix the carry with three zeros

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APTITUDE CRACK · Accepted Answer

D add 0110 to the lowest order code group because a carry was generated and then prefix the carry with three zeros No answer description is available.

Digital Arithmetic Operations and Circuits

The BCD addition of 910 and 710 will give initial code groups of 1001 + 0111. Addition of these groups generates a carry to the next higher position. The correct solution to this problem would be to:

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Digital Arithmetic Operations and Circuits

The BCD addition of 910 and 710 will give initial code groups of 1001 + 0111. Addition of these groups generates a carry to the next higher position. The correct solution to this problem would be to:

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