The BCD addition of 910 and 710 will give initial code groups of 1001 + 0111. Addition of these groups generates a carry to the next higher position. The correct solution to this problem would be to:-A-ignore the lowest order code group because 0000 is a valid code group and prefix the carry with three zerosB-add 0110 to both code groups to validate the carry from the lowest order code groupC-disregard the carry and add 0110 to the lowest order code groupD-add 0110 to the lowest order code group because a carry was generated and then prefix the carry with three zeros-D-add 0110 to the lowest order code group because a carry was generated and then prefix the carry with three zeros

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D add 0110 to the lowest order code group because a carry was generated and then prefix the carry with three zeros No answer description is available.

Digital Arithmetic Operations and Circuits - Technical MCQs

The BCD addition of 910 and 710 will give initial code groups of 1001 + 0111. Addition of these groups generates a carry to the next higher position. The correct solution to this problem would be to:

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Digital Arithmetic Operations and Circuits - Technical MCQs

The BCD addition of 910 and 710 will give initial code groups of 1001 + 0111. Addition of these groups generates a carry to the next higher position. The correct solution to this problem would be to:

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