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Time Response of Reactive Circuits

Q1:

The output voltage in the given circuit is _____ at the end of the second pulse.

A 1.06 V

B 7.56 V

C 3.32 V

D 12 V

ANS:C - 3.32 V

RC = 50 * 10^3 * 56 * 10^-9 = 2800 * 10^-6 s =2.8 ms.

For first pulse, Vc = Vo[1-e^(-τ/RC)] = 5(1-e^-2.8 ms / 2.8 ms) = 5(1-0.367) = 5 * 0.933 = 4.665 V.

Between first and second pulse, Vc = [Vi * e^(-τ/RC)] = 4.665 * (e^-5.6 ms / 2.8 ms) = 4.665 * 0.135 = 0.629 V = 0.63 V(approx).

For second pulse, Vc = [Vf + (Vi - Vf) * e^(-τ/RC)] = 5 + (0.63-5)e^-2.8ms /2.8ms = 5 +(-4.37) * 0.367 = 3.39 V.



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