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Problems on Ages

Q1: The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

A 8, 20, 28

B 16, 28, 36

C 20, 35, 45

D None of these

ANS:B - 16, 28, 36

Let their present ages be 4x, 7x and 9x years respectively. Then, (4x - 8) + (7x - 8) + (9x - 8) = 56  20x = 80  x = 4.  Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.



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