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Boolean Algebra and Logic Simplification

Q1: The truth table for the SOP expression  has how many input combinations?

A 1

B 2

C 4

D 8

ANS:D - 8

Here we simplify it multiply with ab(c+c')*ab+(a+a')*b'c.
Here we get,
Abc+abc'+ab'c+a'b'c.
Hence there is 3input a b c.
Thus total no of IP combination is 2pow 3 =.8.



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