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Counters

Q1: Using four cascaded counters with a total of 16 bits, how many states must be deleted to achieve a modulus of 50,000?

A 50,000

B 65,536

C 25,536

D 15,536

ANS:D - 15,536

We are using four cascaded counters means 16 bits it's given so 2^16-50000 will be answer because 16 bits is given we can find the total count by 2^16 these can be the total count which can be formed by 16 combinations and it is saying useful are 50000 so unused is 65536-50000.



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