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Field Effect Transistors (FET)

Q1:

Using voltage-divider biasing, what is the voltage at the gate VGS?

mcq13_1010_1.gif

A 5.2 V

B 4.2 V

C 3.2 V

D 2.2 V

ANS:A - 5.2 V

V(GS)=V(DD)*R2/(R1+R2)
Where V(GS)= V(in)
V(DD) = VCC



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