Time Response of Reactive Circuits
Q1:
 What is the voltage across the inductor in the given circuit on the falling edge of the first input pulse?A –0.2 V
B 0.2 V
C –9.8 V
D 9.8 V
ANS:A - –0.2 V Since it is an inductor, at t=0, VL = Vmax = 10 V. The voltage across the inductor decreases as the current increases opposite of that of the capacitor therefore inductor discharges in the opposite direction thus VL = -Vin^-t/(L/R) = -0.183 = -0.2 V. Share : |
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