Time Response of Reactive Circuits - Technical MCQs

Q1:

What is the voltage across the inductor in the given circuit on the falling edge of the first input pulse?

A –0.2 V

B 0.2 V

C –9.8 V

D 9.8 V

ANS:A - –0.2 V

Since it is an inductor, at t=0, VL = Vmax = 10 V. The voltage across the inductor decreases as the current increases opposite of that of the capacitor therefore inductor discharges in the opposite direction thus VL = -Vin^-t/(L/R) = -0.183 = -0.2 V.