[Solved] What will be the output of the program ? #include<stdio.h> int main() { FILE *ptr; char i; ptr = fopen('myfile.c', 'r'); while((i=fgetc(ptr))!=NULL) printf('%c', i); return 0; } - Programming - C Programming - Input / Output

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What will be the output of the program ?

#include<stdio.h>

int main()
{
    FILE *ptr;
    char i;
    ptr = fopen('myfile.c', 'r');
    while((i=fgetc(ptr))!=NULL)
        printf('%c', i);
    return 0;
}

A Print the contents of file "myfile.c"

B Print the contents of file "myfile.c" upto NULL character

C Infinite loop

D Error in program

ANS:A - Print the contents of file "myfile.c"

The program will generate infinite loop. When an EOF is encountered fgetc() returns EOF. Instead of checking the condition for EOF we have checked it for NULL. so the program will generate infinite loop.

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Input / Output

What will be the output of the program ?
`#include<stdio.h> int main() { FILE *ptr; char i; ptr = fopen('myfile.c', 'r'); while((i=fgetc(ptr))!=NULL) printf('%c', i); return 0; }`

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Input / Output

What will be the output of the program ? #include<stdio.h> int main() { FILE *ptr; char i; ptr = fopen('myfile.c', 'r'); while((i=fgetc(ptr))!=NULL) printf('%c', i); return 0; }

Solution

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What will be the output of the program ?
`#include<stdio.h> int main() { FILE *ptr; char i; ptr = fopen('myfile.c', 'r'); while((i=fgetc(ptr))!=NULL) printf('%c', i); return 0; }`

For help Students Orientation
Mcqs Questions